![]() ![]() You can search for files by name, owner, group, type, permissions, date, and other criteria. The simplest form of the command searches for files in the current directory and recursively through its subdirectories that match the supplied search criteria. 5 Answers Sorted by: 320 Use the -o flag between different parameters. Here i am reading the files by giving the path to them and whatever i am reading i am keeping them inside a variable I, which i will quote at a later point while processing it to preserve the spaces so as to process it correctly. ( /. )\1p' sort -u It outputs nothing for: Files with no extension Files with names that end in a dot Hidden files It also might be useful to pipe it to sort uniq -c. The find command allows you to search for files for which you know the approximate filenames. SCRIPT : find /path/to/files/ -iname "*jpg" | \ This is one of the basic ways of doing it, however, the other answers provided by the other people here work just as well. We here will read all the files present and keep them in a variable, next time when doing the desired processing we just will have to keep that variable inside quotes which will preserve the file names with spaces. sql (where equates to /home/yourusername/), or. ![]() Solution : So one of the better known ways of doing this is to do a clean read. To find files/directories with a specific extension, use a wildcard: find. So they don't understand that they need to handle spaces as well, as the file name can consist of 2 or more words with spaces. Sometimes, people with limited knowledge and having a misconception of file and folder structure tend to forget that " In UNIX Everything is a file". What you have mentioned is one of the basic problems that people face, when they try to read file names. To find a file by name with the find command, you would use the following syntax: find -name ' query ' This will be case sensitive, meaning a search for query is different from a search for Query. ![]()
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